Two hollow conducting spheres of radii $R_{1}$ and $R_{2}$ $\left(R_{1}>>R_{2}\right)$ have equal charges. The potential would be:
NEET 2022, Easy
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$V =\frac{1}{4 \pi \epsilon_{0}} \cdot \frac{ Q }{ R }$
$\frac{1}{4 \pi \epsilon_{0}}=\text { constant }$
$Q =\text { same (Given) }$
$\therefore V \propto \frac{1}{ R }$
$\therefore$ Potential is more on smaller sphere.
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