Two identical air filled parallel plate capacitors are charged to… - Vidyadip

MCQ

Two identical air filled parallel plate capacitors are charged to the same potential in the manner shown by closing the switch $S$. If now the switch $S$ is opened and the space between the plates is filled with a dielectric of relative permittivity $\varepsilon_r$ then:

A
The potential difference as well as charge on each capacitor goes up by a factor $\varepsilon_r.$
B
The potential difference as well as charge on each capacitor goes down by a factor $\varepsilon_r.$
✓
The potential difference across $A$ remains constant and the charge on $B$ remains unchanged.
D
The potential difference across $B$ remains constant while the charge on $A$ remains unchanged.

✓

Answer

Correct option: C.

The potential difference across $A$ remains constant and the charge on $B$ remains unchanged.

After switch $S$ is opened, as the Capacitor $A$ is connected across the battery, its potential difference is fixed at steady state $($i.e., when capacitor is fully charged$).$
Capacitor $B$ is isolated, so its charge gets fixed. But as we insert the dielectric, its capacitance changes, thus its potential difference also changes.

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