MCQ
Two identical capacitors $\mathrm{A}$ and $\mathrm{B}$, charged to the same potential $5\; \mathrm{V}$ are connected in two different circuits as shown below at time $\mathrm{t}=0$ If the charge on capacitors $A$ and $B$ at time $\mathrm{t}=\mathrm{CR}$ is $\mathrm{Q}_{\mathrm{A}}$ and $\mathrm{Q}_{\mathrm{B}}$ respectively, then (Here $e$ is the base of natural logarithm)
- ✓$\mathrm{Q}_{\mathrm{A}}=\mathrm{VC}, \mathrm{Q}_{\mathrm{B}}=\frac{\mathrm{VC}}{\mathrm{e}}$
- B$\mathrm{Q}_{\mathrm{A}}=\frac{\mathrm{CV}}{2}, \mathrm{Q}_{\mathrm{B}}=\frac{\mathrm{VC}}{\mathrm{e}}$
- C$\mathrm{Q}_{\mathrm{A}}=\mathrm{VC}, \mathrm{Q}_{\mathrm{B}}=\mathrm{CV}$
- D$\mathrm{Q}_{\mathrm{A}}=\frac{\mathrm{VC}}{\mathrm{e}}, \mathrm{Q}_{\mathrm{B}}=\frac{\mathrm{CV}}{2}$
