Two identical cells each of emf $1.5\,V$ are connected in series across a $10\,\Omega$ resistance. An ideal voltmeter connected across $10\,\Omega$ resistance reads $1.5\,V$. The internal resistance of each cell is $......\Omega$.
JEE MAIN 2023, Medium
Download our app for free and get started
$V = I \times 10$
$1.5=\left(\frac{3}{10+2 r }\right) \times 10$
$r =5\,\Omega$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
The heating coils rating at $220\, volt$ and producing $50\, cal/sec$ heat are available with the resistances $55\,\Omega $ , $110\,\Omega$ , $220\,\Omega $ and $440\,\Omega $. The heater of maximum power will be of............. $\Omega$
A potentiometer has uniform potential gradient across it. Two cells connected in series $(i)$ to support each other and $(ii)$ to oppose each other are balanced over $6\,m$ and $2\,m$ respectively on the potentiometer wire. The $e.m.f.$’s of the cells are in the ratio of
A meter bridge set up as shown to determine end correction at $A$ and $B$. When a resistance of $15\ \Omega$ is used in left gap and of $20\ \Omega$ in right gap, then null point comes at a distance $42\ cm$ from $A$. When these resistances are interchanged null point comes at a distance $57\ cm$ from $A$. Values of end corrections are
A potentiometer is connected between $A$ and $B$ and the balance point is obtained at $203. 6\,cm$. When the end of the potentiometer connected to $B$ is shifted to $C$, then the balance point is obtained at $24.6\,cm$. If now the potentiometer be connected between $B$ and $C$, the balance point will be at ................. $cm$
Two batteries of different $e.m.f.'s$ and internal resistance connected in series with each other and with an external load resistor. The current is $3.0 \,A$. When the polarity of one battery is reversed, the current becomes $1.0 \,A$. The ratio of the $e.m.f.'s$ of the two batteries is ............
Consider the circuits shown in the figure. Both the circuits are taking same current from battery but current through $R$ in the second circuit is $\frac{1}{{10}}$$^{th}$ of current through $R$ in the first circuit. If $R$ is $11$ $\Omega$, the value of $ R_1$ ................ $\Omega$