MCQ
Two identical pendulums oscillate with a constant phase difference $\frac{\pi}{4}$ and same amplitude. If the maximum velocity of one is $v$, the maximum velocity of the other will be ........
  • $v$
  • B
    $\sqrt{2} v$
  • C
    $2 v$
  • D
    $\frac{v}{\sqrt{2}}$

Answer

Correct option: A.
$v$
a
(a)

If the phase difference is constant, they are moving with same frequency and $\omega$.

Since maximum velocity $A \omega=v$ (given)

Maximum velocity of other will still be $v$.

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