MCQ
Two identical pendulums oscillate with a constant phase difference $\frac{\pi}{4}$ and same amplitude. If the maximum velocity of one is $v$, the maximum velocity of the other will be ........
- ✓$v$
- B$\sqrt{2} v$
- C$2 v$
- D$\frac{v}{\sqrt{2}}$
If the phase difference is constant, they are moving with same frequency and $\omega$.
Since maximum velocity $A \omega=v$ (given)
Maximum velocity of other will still be $v$.
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