Question
Two interfering waves of the same frequency are in phase but have different amplitudes $A_1$ and $A _2$. What can you say about the intensity of the resultant wave?

Answer

The two waves interfere in phase. Thus, the amplitude and hence the intensity of the resultant wave is maximum, $I_{\max } \propto\left(A_{\min }\right)^2$ where $\left(A_{\max }\right)^2=\left(A_1+A_2\right)^2$.

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