${ }_{1}^{2} X +{ }_{1}^{2} X ={ }_{2}^{4} Y$
The binding energies per nucleon ${ }_{1}^{2} X$ and ${ }_{2}^{4} Y$ are $1.1\,MeV$ and $7.6\,MeV$ respectively. The energy released in this process is $MeV$.
$=7.6 \times 4-(1.1 \times 2) \times 2$
$=30.4-4.4$
$=26\,MeV$
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Statement$ -1$ : When a charge $q$ is take from the centre of the surface of the sphere its potential energy changes by $\frac{{q\rho }}{{3{\varepsilon _0}}}$
Statement$ -2$ : The electric field at a distance $r(r < R)$ from centre of the sphere is $\frac{{\rho r}}{{3{\varepsilon _0}}}$
