MCQ
Two lines $AB$ and $CD$ intersect at $O$. If $\angle\text{AOC}+\angle\text{COB}+\angle\text{BOD}=270^\circ,$ then $\angle\text{AOC}=$
  • A
    $180^\circ$
  • B
    $70^\circ$
  • C
    $80^\circ$
  • $90^\circ$

Answer

Correct option: D.
$90^\circ$
Given that,
$AB$ and $CD$ intersect at $O$
$\angle\text{AOC}+\angle\text{COB}+\angle\text{BOD}=270^\circ\text{(i)}$
$\angle​\text{COB}+\angle\text{BOD}=180^\circ$ (Linear pair) $(ii)$
Using $(ii)$ in $(i)$, we get
$\angle​\text{AOC}+180^\circ=270^\circ$
$​\text{AOC}=90^\circ.$

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