Question
Two masses M and m are connected at the two ends of an inextensible, light string. The string passes over a smooth frictionless pulley. Calculate the acceleration of the masses and the tension in the string. M is heavier than m.
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Answer
The pulley is frictionless, massless and fixed. The free body diagram for the two masses are shown along with the equation. 
Mg - T = Ma T - mg = ma Solving the equation, we get $\text{a}=\frac{(\text{M}-\text{m})\text{g}}{\text{M}+\text{m}}$ and $\text{T}=\frac{(2\text{Mm})\text{g}}{\text{M}+\text{m}}$
Mg - T = Ma T - mg = ma Solving the equation, we get $\text{a}=\frac{(\text{M}-\text{m})\text{g}}{\text{M}+\text{m}}$ and $\text{T}=\frac{(2\text{Mm})\text{g}}{\text{M}+\text{m}}$Need a full question paper?
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