MCQ
Two masses $M$ and $m$ are connected by a weightless string. They are pulled by a force $F$ on a frictionless horizontal surface., the acceleration of mass $m$ is
- A$\frac{F}{m}$
- ✓$\frac{{F - T}}{m}$
- C$\frac{{F + T}}{m}$
- D$\frac{F}{M}$
✓
Answer
Correct option: B.
$\frac{{F - T}}{m}$
b
(b) Net force on mass $m$, $ma = F - T$$\therefore $ $a = \frac{{F - T}}{m}$
(b) Net force on mass $m$, $ma = F - T$$\therefore $ $a = \frac{{F - T}}{m}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$M$ grams of steam at $100^{\circ} \mathrm{C}$ is mixed with $200\; \mathrm{g}$ of ice at its melting point in a thermally insulated container. If it produces liquid water at $40^{\circ} \mathrm{C}$ [heat of vaporization of water is $540 \;cal/\mathrm{g}$ and heat of fusion of ice is $80 \;\text { cal/g }]$ the value of $\mathrm{M}$ is
→The magnetic moments associated with two closely wound circular coils $A$ and $B$ of radius $r_A=10 cm$ and $r_B=20 cm$ respectively are equal if: (Where $N _A, I _{ A }$ and $N _B, I _{ B }$ are number of turn and current of $A$ and $B$ respectively)
→A particle is projected with a velocity of $30\,m / s$, at an angle of $\theta_0=\tan ^{-1}\left(\frac{3}{4}\right)$ After $1\,s$, the particle is moving at an angle $\theta$ to the horizontal, where $\tan \theta$ will be equal to $\left(g=10\,m / s ^2\right)$
→The electric field associated with an em wave in vacuum is given by $\vec{E}=\hat{i} 40 \cos \left(k z-6 \times 10^{8} t\right)$ where $E, x$ and $t$ are in $volt/m,$ meter and seconds respectively. The value of wave vector $k$ is....$ m^{-1}$
→An object and a screen are fixed on the uprights of an optical bench. The distance between them is $100\, cm$. A convex lens is placed in between the object and the screen and the position of the lens is so adjusted that the image of the object is formed on the screen at two conjugate positions of the lens. The distance between these conjugate positions of the lens is $40\, cm$. What is the focal length of the lens......$cm$
→$A $ magnet freely suspended in a vibration magnetometer makes $10 $ oscillations per minute at a place $A$ and $20 $ oscillations per minute at a place $B$. If the horizontal component of earth’s magnetic field at $A$ is $36 \times {10^{ - 6}}\,T$, then its value at $B$ is
→Consider an initially pure $M$ gm sample of$_ A{X}$, an isotope that has a half life of $T$ hour, what is it’s initial decay rate ($N_A$ = Avogrado No.)
→The magnetic field induction produced at the centre of orbit due to an electron revolving in $n^{\text {th }}$ orbit of hydrogen atom is proportional to
→A flexible circular loop $20\ cm$ in diameter lies in a magnetic field of magnitude $B = 1$ Tesla, directed into the plane of page as shown. The loop is pulled at the points indicated by the arrows forming a loop of zero area in $0.314\ sec$ . The average emf induced in the loop is.....$V$
→If $f _{0}=5\, cm , \lambda=6000\, \mathring A, a =1 \,cm$ for a microscope, then what will be its resolving power?
→