Two metallic plates form a parallel plate capacitor. The distance… - Vidyadip

MCQ

Two metallic plates form a parallel plate capacitor. The distance between the plates is $'d'.$ A metal sheet of thickness $\frac{d}{2}$ and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor $?$

✓
$2: 1$
B
$1: 2$
C
$1: 4$
D
$4: 1$

✓

Answer

Correct option: A.

$2: 1$

a
$C _{1}=\frac{\in_{0} A }{ d }$

$C _{2}=\frac{\in_{0} A }{\frac{ d }{2}+\frac{ d / 2}{\propto}}=\frac{2 \in_{0} A }{ d }$

$\frac{ C _{2}}{ C _{1}}=\frac{2}{1}$

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