Question
Two metals A and B have work functions 4eV and 10eV respectively. Which metal has the higher threshold wavelength?

Answer

Work function $\text{W}=\text{h}\nu_0=\frac{\text{hc}}{\lambda_0}$
$\Rightarrow\ \lambda_0\propto\frac{1}{\text{W}}$
As $\text{W}_\text{A}<\text{W}_\text{B};\ (\lambda_0)_\text{A}>(\lambda_0)_\text{B}$
i.e., threshold wavelength of metal A is higher.

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