
$B_{\text {net }}=\frac{\mu_0 I}{2 \pi(d)}$
Due to long wire along $x$ - axis,
magnetic field at $P$ is $B_x=\frac{\mu_0 I}{2 \pi(3)} \odot$
Due to long wire along $y$-axis,
magnetic field at $P$ is $B_y=\frac{\mu_0 I}{2 \pi(2)} \otimes$
Net magnetic field at $P$ is $B_{\text {net }}=B_y-B_x$
$B_{\text {net }}=\frac{\mu_0 I}{2 \pi(2)}-\frac{\mu_0 l}{2 \pi(3)}$
$\Rightarrow B_{\text {net }}=\frac{\mu_0 I}{12 \pi} \otimes$
