Question
Two number differ by $4$ and their product is $192$. Find the numbers.

Answer

Let first number $= x$
Then second number $= x - 4$
According to the condition,
$ \Rightarrow x(x-4)=192 $
$ \Rightarrow x^2-4 x-192=0 $
$ \Rightarrow x^2-16 x+12 x-192=0 $
$ \Rightarrow x(x-16)+12(x-16)=0 $
$ \Rightarrow(x-16)(x+12)=0$
Either $x - 16 = 0,$ then $x = 16$
Or $x + 12 = 0,$ then $x = -12$
  1. If $x = 16$, then
First number $= 16$ and second number $= 16 - 4 = 12$
  1. If $x = -12,$ then
First number = -12 and second number $= -12 - 4 = -16$
Hence numbers are $16, 12$ or $-12, -16$

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