Question
Two numbers are selected at random (without replacement) from the first six positive integers. Let X denote the larger of the two numbers obtained. Find the probability distribution of the random variable X, and hence find the mean of the distribution.

Answer

Total number of ways of selecting two numbers= 2C6 = 15
Values of x (larger of the two) can be 2, 3, 4, 5, 6
$\text{ P(x = 2) } = \frac{1}{15},\text{ P(x = 3)} = \frac{2}{15},\text{ P(x = 4)} = \frac{3}{15}$
$\text{P(x = 5)} = \frac{4}{15}\text{ and P(x = 6)} = \frac{5}{15}$
$\therefore$ Distribution can bewritten as
x:  2 3 4 5 6
P(x): $\frac{1}{15}\frac{2}{15}\frac{3}{15}\frac{4}{15}\frac{5}{15}$
x P(x): $\frac{2}{15}\frac{6}{15}\frac{12}{15}\frac{20}{15}\frac{30}{15}$
$\text{ Mean } = \sum\text{x}\text{ P(x)} = \frac{70}{15}= \frac{14}{3}.$

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