MCQ
Two numbers are selected randomly from the set $S = \{ 1,\,2,\,3,\,4,\,5,\,6\} $ without replacement one by one. The probability that minimum of the two numbers is less than $4$ is
  • A
    $\frac{1}{{15}}$
  • B
    $\frac{{14}}{{15}}$
  • C
    $\frac{1}{5}$
  • $\frac{4}{5}$

Answer

Correct option: D.
$\frac{4}{5}$
d
(d) Total ways $= 2\,! \,^6{C_2} = 30$

Favourable cases $ = 30 - 6 = 24$

$\therefore$ Required probability $ = \frac{{24}}{{30}} = \frac{4}{5}$.

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