MCQ
Two opposite charged particles oscillate about their mean equilibrium position in free space, with a frequency of 109Hz. The wavelength of the corresponding electromagnetic wave produced is ______:
- A0.3m
- B109m
- C3×1017m
- D3.3m
✓
Answer
- 0.3m
Explanation:
Electromagnetic wave V = 3×108m/s
Given frequency (f) = 109Hz
$\text{V}=\text{f}\lambda$
$\lambda=\frac{\text{V}}{\text{f}}$
$=\frac{3 \times 10^8} {10^9}$
= 0.3m
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