MCQ
Two oscillating systems; a simple pendulum and a vertical spring-mass-system have same time period of motion on the surface of the Earth. If both are taken to the moon, then-
  • Time period of the simple pendulum will be more than that of the spring-mass system.
  • B
    Time period of the simple pendulum will be equal is that is of the spring-mass system.
  • C
    Time period of the simple pendulum will be less than of the spring-mass system.
  • D
    Nothing can be said definitely without observation.

Answer

Correct option: A.
Time period of the simple pendulum will be more than that of the spring-mass system.
a
(a)

For simple pendulum: $T =2 \pi \sqrt{\frac{\ell}{ g }}$ As g will decrease on moon, time period will increase

For spring mass system : $T=2 \pi \sqrt{\frac{m}{k}}$

It will not change and remains the same

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