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STD 12 - 2. Electric potential and capacitance — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 2. Electric potential and capacitance4 Marks
MCQ
Two parallel large thin metal sheets have equal surface charge densities $\left(\sigma=26.4 \times 10^{-12} C / m ^{2}\right)$ of same signs. The electric field between these sheet is
  • A
    $1.5 N / C$
  • B
    $1.5 \times 10^{-10} N / C$
  • ✓
    Zero
  • D
    $3 \times 10^{-10} N / C$
✓

Answer

Correct option: C.
Zero
c
The electric field between the thin sheets is given as,

$E=\frac{\left(\sigma_{1}-\sigma_{2}\right)}{2 \epsilon_{0}}$

Here, $\sigma_{1}=\sigma_{2} E =0$

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