Two pendulums have time periods $T$ and $\frac{{5T}}{4}.$They start $S.H.M.$ at the same time from the mean position. What will be the phase difference between them after the bigger pendulum has complete one oscillation ..... $^o$
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(b) $\frac{{5T}}{4} = T + \frac{T}{4}$
By the time, the bigger pendulum makes one full oscillation, the smaller pendulum will make $\left( {1 + \frac{1}{4}} \right)$ oscillation. The bigger pendulum will be in the mean position and the smaller one will be in the positive extreme position. Thus, phase difference $= 90°$
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