MCQ
Two radiations having energies $E_1$ and $E_2$ as $15\,eV$ and $45\, eV$ respectively  then the relationship in between $\lambda_1$ and $\lambda_2$ will be
  • A
    $\lambda_1 = \lambda_2$
  • $\lambda_1 = 3 \lambda_2$
  • C
    $\lambda_1 = \lambda_2/3$
  • D
    $\lambda_1 = 9\lambda_2$

Answer

Correct option: B.
$\lambda_1 = 3 \lambda_2$
b
$ \mathrm{E}_{1}=15\, \mathrm{eV}  \Rightarrow \frac{\mathrm{hc}}{\lambda_{1}}=15\, \mathrm{eV} .........(i)$

$ \mathrm{E}_{2}=45\, \mathrm{eV}  \Rightarrow \frac{\mathrm{hc}}{\lambda_{2}}=45 \,\mathrm{eV} .........(ii)$

$ \frac{\lambda_{2}}{\lambda_{1}}=\frac{1}{3} $

$ \lambda_{1} =3 \lambda_{2}$

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