MCQ
Two rods $A$ and $B$ of same cross-sectional are $A$ and length $l$ connected in series between a source $(T_1 = 100^o C)$ and a sink $(T_2 = 0^o C)$ as shown in figure. The rod is laterally insulated If $G_A$ and $G_B$ are the temperature gradients across the rod $A$ and $B$, then
- A$\frac{{{G_A}}}{{{G_B}}} = \frac{3}{1}$
- ✓$\frac{{{G_A}}}{{{G_B}}} = \frac{1}{3}$
- C$\frac{{{G_A}}}{{{G_B}}} = \frac{3}{4}$
- D$\frac{{{G_A}}}{{{G_B}}} = \frac{4}{3}$
