MCQ
Two simple harmonic motions are represented by the equations $y_1=0.1 \sin \left(100 \pi t+\frac{\pi}{3}\right)$ and $y_2=0.1 \cos \pi t .$ The phase difference of the velocity of particle $1$ with respect to the velocity of particle $2$ is
- A$\frac{-\pi}{3}$
- B$\frac{\pi}{6}$
- ✓$\frac{-\pi}{6}$
- D$\frac{\pi}{3}$
