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STD 11 - 5. work,energy,power and collision — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 5. work,energy,power and collision4 Marks
MCQ
Two smooth objects with a coefficient of restitution $e,$ collide directly and bounce as shown. Newton's law of restitution gives
  • A
    $e \times 4u = v_2 + v_1$
  • B
    $e \times 2u = v_1 + v_2$
  • ✓
    $e \times 2u = v_2 - v_1$
  • D
    it cannot be applied as the masses are not known
✓

Answer

Correct option: C.
$e \times 2u = v_2 - v_1$
c
$H=20+15=35 \mathrm{m}$

${\mathrm{e}=\frac{\mathrm{v}_{2}-\mathrm{v}_{1}}{\mathrm{u}_{1}-\mathrm{u}_{2}}}$

${\mathrm{e}=\frac{\mathrm{v}_{2}-\mathrm{v}_{1}}{3 \mathrm{u}-\mathrm{u}_{1}}}$

${\mathrm{e}(2 \mathrm{u})=\mathrm{v}_{2}-\mathrm{v}_{1}}$

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