Download App

5.work,energy,power and collision — Physics STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 SciencePhysics5.work,energy,power and collision1 Mark
MCQ
Two solid rubber balls $A$ and $B$ having masses $200$ and $400\, gm$ respectively are moving in opposite directions with velocity of $A$ equal to $0.3 \,m/s$. After collision the two balls come to rest, then the velocity of $B$ is .............. $\mathrm{m} / \mathrm{s} $
  • A
    $0.15$
  • B
    $1.5 $
  • ✓
    $-0.15$
  • D
    None of the above
✓

Answer

Correct option: C.
$-0.15$
c
(c)Initial linear momentum of system = ${m_A}{\vec v_A} + {m_B}{\vec v_B}$
$= 0.2 × 0.3 + 0.4 × v_B$
Finally both balls come to rest
 final linear momentum $= 0$ 
By the law of conservation of linear momenum
$0.2 × 0.3 + 0.4 × v_B = 0$
 ${v_B} = - \frac{{0.2 \times 0.3}}{{0.4}} = - 0.15\;m/s$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 5.work,energy,power and collision→5.work,energy,power and collision — all question types→Physics STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to $A$ and $T,$  respectively. At time $t=0$ one particle has displacement $A$ while the other one has displacement $\frac {-A}{2}$ and they are moving towards each other. If they cross each other at time $t,$ then $t$ is
→
If an average person jogs, he produces 14.5 × 103 cal/ min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1kg requires 580 × 103cal for evaparation) is
→
$A$ ring of mass $M$ and radius $R$ sliding with a velocity $v_0$ suddenly enters into rough surface where the coefficient of friction is $\mu$ , as shown in figure.  Choose the correct statement $(s)$
→
A stone of mass $1 \,kg$ is tied with a string and it is whirled in a vertical circle of radius $1 \,m$. If tension at the highest point is $14 \,N$, then velocity at lowest point will be ............ $m / s$
→
Values for latent heat in Column$-\,I$ and its values are given in Column$-\,II$. Match the followings :
Column $-\,I$ Column $-\,II$
$(a)$ Latent heat of vaporization $L_V$ $(i)$ $22.6\, \times \,{10^5}\,J\,/kg$
$(b)$ Latent heat of fusion $L_f$ $(ii)$ $33.3\, \times \,{10^5}\,J\,/kg$
    $(iii)$ $3.33\, \times \,{10^5}\,J\,/kg$
→
A particle executing simple harmonic motion with an amplitude A and angular frequency $\omega$ The ratio of maximum acceleration to the maximum velocity of the particle is:
→
A mass is performing vertical circular motion (see figure). If the average velocity of the particle is increased, then at which point is the maximum breaking possibility of the string:
→
Two projectile thrown at $30^{\circ}$ and $45^{\circ}$ with the horizontal respectively, reach the maximum height in same time. The ratio of their initial velocities is
→
$Assertion :$ The pressure of water reduces when it flows from a narrow pipe to a wider pipe.
$Reason :$ Since for wider pipe area is large, so flow of speed is small and pressure also reduces proportionately.
→
Find velocity of block ' $B$ ' at the instant shown in figure $........\,m/s$
→