MCQ
Two springs $A$ and $B$ having spring constant $K_{A}$ and $K_{B}\left(K_{A}=2 K_{B}\right)$ are stretched by applying force of equal magnitude. If energy stored in spring $A$ is $E_{A}$ then energy stored in $B$ will be
  • $2 E_{A}$
  • B
    $E_{A}/4$
  • C
    $E_{A}/2$
  • D
    $4 E_{A}$

Answer

Correct option: A.
$2 E_{A}$
a
Energy $=\frac{1}{2} K x^{2}=\frac{1}{2} \frac{F^{2}}{K}$.

$\frac{K_{A}}{K_{B}}=2$

$\frac{E_{A}}{E_{B}}=\frac{1}{2}$

$E_{B}=2 E_{A}$

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