If range is same then, one angle is $\theta$ and other angle is $(90-\theta)$
$\Rightarrow h_1=\frac{u^2 \sin ^2 \theta}{2 g}, h_2=\frac{u^2 \sin ^2(90-\theta)}{2 g}$
$h_1=\frac{u^2 \sin ^2 \theta}{2 g}, h_2=\frac{u^2 \cos ^2 \theta}{2 g}$
So, $h_1+h_2 \Rightarrow \frac{u^2 \sin ^2 \theta}{2 g}+\frac{u^2 \cos ^2 \theta}{2 g}=\frac{u^2}{2 g}\left(\sin ^2 \theta+\cos ^2 \theta\right)$
$h_1+h_2=\frac{u^2}{2 g}$
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(Take $\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9} Nm ^{2} C ^{-2}$ )
