Question
Two straight lines AB and CD cut each other at O. If $\angle\text{BOD}=63^\circ,$ then $\angle\text{BOC}=$
✓
Answer
- 117º
Solution:
$\angle\text{BOD}+\angle\text{BOC}=180^\circ$ (Linear pair)
$63^\circ+\angle\text{BOC}=180^\circ$
$\text{BOC}=117^\circ.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
After simplification, $\frac{13^{\frac{1}{5}}}{13^{\frac{1}{3}}}$ is:
→- $13^\frac{2}{15}$
- $13^\frac{8}{15}$
- $13^\frac{1}{3}$
- $13^\frac{-2}{15}$
The cost of constructing a wall $8m$ long, $4m$ high and $10\ cm$ thick at the rate of $₹ 25$ per $m^3$ is:
→A surface of shape has:
The mean of n observations is $\overline{\text{X}}$ If each observation is multiplied by $k,$ the mean of new observations is:
→If the volume of two cones are in the ratio $1 : 4$ and their diameters are in the ratio $4 : 5,$ then the ratio of their heights, is:
→Each side of an equilateral triangle measures $10\ cm.$ Then the area of the triangle is:
→→
The value of $x^3 - 8y^3 - 36xy - 216,$ when $x = 2y + 6$ is:
→If the height of a cylinder is doubled and radius remains the same, then volume will be: