MCQ
Two straight parallel wires, both carrying $10$ ampere in the same direction attract each other with a force of $1\times 10^{-3}N$. If both currents are doubled, the force of attraction will be
  • A
    $1\times 10^{-3}N$
  • B
    $2 \times 10^{-3}N$
  • $4 \times 10^{-3}N$
  • D
    $0.25 \times 10^{-3}N$ 

Answer

Correct option: C.
$4 \times 10^{-3}N$
$4 \times 10^{-3}N$

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