MCQ
Two supplementary angles are in the ratio $3 : 2.$ The smaller angle measures$?$
- A$108^\circ $
- B$81^\circ$
- ✓$72^\circ$
- D$68^\circ $
Given two supplementary angles are in the ratio $3 : 2.$
Let the measurement of the angles be $3x$ and $2x.$
Two angles are said to be supplementary if they sum upto $180^\circ .$
Then we have, $3x + 2x = 180^\circ $
$5x = 180^\circ $ or, $x = 36^\circ .$
So the smaller angle is $36^\circ \times 2 = 72^\circ .$
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