Question
Two supplementary angles differ by $44^\circ $. Find the angles.
✓
Answer
Sum of two supplementary angles $= 180^\circ$
Let first angle $= x$
Then second angle $= 180^\circ - x x - (180^\circ - x) = 44^\circ$
$ \Rightarrow x - 180^\circ + x = 44^\circ$
$\Rightarrow 2x = 44^\circ + 180^\circ = 224^\circ $
$\Rightarrow 2x = 224^\circ$
$ \Rightarrow x = 112^\circ$
First angle $= 112^\circ$ And second angle$ = 180^\circ - 112^\circ = 68^\circ$
Hence angles are $68^\circ , 112^\circ$.
Let first angle $= x$
Then second angle $= 180^\circ - x x - (180^\circ - x) = 44^\circ$
$ \Rightarrow x - 180^\circ + x = 44^\circ$
$\Rightarrow 2x = 44^\circ + 180^\circ = 224^\circ $
$\Rightarrow 2x = 224^\circ$
$ \Rightarrow x = 112^\circ$
First angle $= 112^\circ$ And second angle$ = 180^\circ - 112^\circ = 68^\circ$
Hence angles are $68^\circ , 112^\circ$.
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