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Waves — Physics STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 SciencePhysicsWaves3 Marks
Question
Two tuning forks A and B when sounded together give 4 beats/ sec, A in unison with the note emitted by a length 0.96m of a sonometer wire under a certain tension while B is in unison with 0.97m of the same wire under the same tension. Find the frequencies of the forks.
✓

Answer

Let the frequency of the fork A be n. Since A is in unison with a smaller length of the sonometer wire than B which is in unison with a larger length of the wire, the frequency of fork A should be larger than that of B.
$\therefore$ frequency of fork B = (v - 4)Hz
Now v × 0.96 = (v - 4)(0.97)
$\frac{\text{v}-4}{\text{v}}=\frac{96}{97}$
$1-\frac{4}{\text{v}}=1-\frac{1}{97}$
$\frac{4}{\text{v}}=\frac{1}{97}$
$\text{v}=4\times97=388\text{Hz}$
$\therefore$ The frequency of fork A = 388Hz
and that of B = 384Hz.

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