MCQ
Two uniform rods of equal length but different masses are rigidly joined to form an $L$ -shaped body, which is then pivoted as shown. If in equilibrium the body is in the shown configuration, ratio $M/m$ will be:
  • A
    $2$
  • B
    $3$
  • C
    $\sqrt 2 $
  • $\sqrt 3 $

Answer

Correct option: D.
$\sqrt 3 $
d
Taking Moments about point $'O'$

clockwise moments $=$ Anticlockwise moments, $M g \times \frac{l}{2} \sin \left(30^{\circ}\right)=m g \times \frac{l}{2} \sin \left(60^{\circ}\right)$

$\Rightarrow \frac{M}{2}=m \frac{\sqrt{3}}{2}$

$\therefore \frac{M}{m}=\sqrt{3}$

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