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STD 11 - 13. oscillations — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 13. oscillations4 Marks
Question
Two waves executing simple harmonic motion travelling in the same direction with same amplitude and frequency are superimposed. The resultant amplitude is equal to the $\sqrt{3}$ times of amplitude of individual motions. The phase difference between the two motions is $.....(degree)$
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Answer

$A _{\text {resultrant }}=\sqrt{ A _{1}^{2}+ A _{2}^{2}+2 A _{1} A _{2} \cos \phi}$ 

$\sqrt{3} A =\sqrt{ A ^{2}+ A ^{2}+2 A ^{2} \cos \phi}$

$3 A ^{2}=2 A ^{2}+2 A ^{2} \cos \phi$

$\cos \phi=\frac{1}{2}$

$\therefore \phi=60^{\circ}$

$\therefore \text { Phase difference }=60 \text { degree }$

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