Two wires that are made up of two different materials whose specific resistance are in the ratio 2 : 3, length 3 : 4 and

Q: Two wires that are made up of two different materials whose specific resistance are in the ratio $2 : 3$, length $3 : 4$ and area $4 : 5$. The ratio of their resistances is

c (c) Resistance $ = \rho \frac{l}{A}$ $\therefore $ $\frac{{{R_1}}}{{{R_2}}} = \frac{{{\rho _1}}}{{{\rho _2}}} \times \frac{{{l_1}}}{{{l_2}}} \times \frac{{{A_2}}}{{{A_1}}} = \frac{2}{3} \times \frac{3}{4} \times \frac{5}{4} = \frac{5}{8}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Two wires that are made up of two different materials whose specific resistance are in the ratio $2 : 3$, length $3 : 4$ and area $4 : 5$. The ratio of their resistances is

A$6:5$
B$6:8$
C$5:8$
D$1:2$

Easy

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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