Question
$\underline{\ \ \ \ \ \text{B}\ \ \ \ \ 6\\\text{+}\ \ 8\ \ \ \ \ \text{A}\ }\\\underline{\ \ \ \ \text{CA}\ \ \ 2\ }$
✓
Answer
Here, $6 + A = 2$, therefore the possible value of $A$ is $6$.
Now, $CA = B + 8 + 1$ $C 6 = B + 9$ i.e. $B + 9$ is a number whose one’s digit is $6$.
Therefore, $B = 7$ and $C = 1$.
Now, $CA = B + 8 + 1$ $C 6 = B + 9$ i.e. $B + 9$ is a number whose one’s digit is $6$.
Therefore, $B = 7$ and $C = 1$.
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