MCQ
$\underset{(A)}{\mathop{\begin{matrix}
   \,\,\,\,\,Ph\,\,\,\,C{{H}_{3}}  \\
   |\,\,\,\,\,\,\,\,\,\,|\,\,  \\
   Ph-C-C-C{{H}_{3}}  \\
   |\,\,\,\,\,\,\,\,\,\,|\,\,\,  \\
   \,OH\,\,\,OH  \\
\end{matrix}}}\,+\underset{(B)}{\mathop{\begin{matrix}
   \,\,\,\,Ph\,\,\,Et  \\
   \,\,|\,\,\,\,\,\,\,\,\,|  \\
   Ph-C-C-Et  \\
   \,\,|\,\,\,\,\,\,\,\,\,|  \\
   \,\,\,\,\,OH\,\,OH  \\
\end{matrix}}}\,\xrightarrow{{{H}_{2}}S{{O}_{4}}}$

 

$(p)$ $\begin{matrix}
   Ph\,\,\,\,\,O\,  \\
   |\,\,\,\,\,\,\,\,||\,\,  \\
   Ph-C-C-C{{H}_{3}}  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,  \\
   C{{H}_{3}}\,\,\,\,\,\,\,\,  \\
\end{matrix}$                                $(q)$ $\begin{matrix}
   \,Ph\,\,\,\,\,O\,  \\
   \,\,|\,\,\,\,\,\,\,\,||  \\
   Ph-C-C-Et  \\
   |\,\,\,\,\,\,\,\,\,\,  \\
   Et\,\,\,\,\,\,\,\,\,\,  \\
\end{matrix}$

$(r)$ $\begin{matrix}
   \,Ph\,\,\,\,\,O\,  \\
   |\,\,\,\,\,\,\,\,\,\,||\,  \\
   Ph-C-C-C{{H}_{3}}  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   Et\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
\end{matrix}$                             $(s)$ $\begin{matrix}
   \,\,\,Ph\,\,\,\,\,O\,  \\
   \,\,|\,\,\,\,\,\,\,\,||  \\
   Ph-C-C-Et  \\
   |\,\,\,\,\,\,\,\,\,\,  \\
   C{{H}_{3}}\,\,\,\,  \\
\end{matrix}$

When $(A)$ and $(B)$ reacts with $H_2SO_4$ products obtained are

  • A
    $p, \,q, \, r, \, s$
  • $p,  \,q$
  • C
    $p,  \,q, \, r$
  • D
    $p,  \,q,  \,s$

Answer

Correct option: B.
$p,  \,q$
b
$(b)$ Pinacol-Pinacolone rearrangment is an intramolecular process.

$\therefore$ no  crossover products are obtained.

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