MCQ
Urea
- AIs an amide of carbonic acid
- ✓It is diamide of carbonic acid
- CGives carbonic acid on hydrolysis
- DResembles carbonic acid
$\mathop {HO - \mathop {\mathop C\limits^{||} }\limits^O - OH}\limits_{{\text{carbonic acid}}} + 2N{H_3}\xrightarrow{{ - {H_2}O}}\mathop {{H_2}N - \mathop {\mathop C\limits^{||} }\limits^O - N{H_2}}\limits_{{\text{Urea}}} $
So two mole of $N{H_3}$ required that why it is the diamide of carbonic acid.
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Statement $I:$ Iron $(III)$ catalyst, acidified $K _{2} Cr _{2} O _{7}$ and neutral $KMnO _{4}$ have the ability to oxidise $I$ to $I _{2}$ independently.
Statement $II$: Manganate ion is paramagnetic in nature and involves $p \pi- p \pi$ bonding.
In the light of the above statements, choose the correct answer from the options.
$(I)$ $CO_2$ $(II)$ $Br_2$ $(III)$ $SnCl_2$ $(IV)$ $HF$ $(V)$ $NMe_3$