Question
Use Huygens's principle to explain the formation of diffraction pattern due to a single slit illuminated by a monochromatic source of light.
When the width of the slit is made double the original width, how would this affect the size and intensity of the central diffraction band?

Answer

Explanation:
As per Huygen's Principle
Net effect at any point = sum total of contribution of all wavelets with proper phase difference At the central Point (O) Contribution from each half in $SS_1$ is in phase with that from the corresponding
part in $SS_2.$ Hence, O is a maxima

At the point M where $\mathrm{SM}-\mathrm{SM}_1=\lambda / 2$ Phase difference between each wavelet from $\mathrm{SS}_1$ and corresponding wavelet from $\mathrm{SS}_2=\lambda / 2$ Hence, M would be a minima. All such points (path difference $=\mathrm{n} \lambda / 2$ ) are also minima. Similarly, all points, for which path difference $=(2 n+1) \lambda / 2$, are maxima but with decreasing intensity. From the figure

Half angular width of central maxima= $\lambda$/a $\therefore$, Size of central maxima will be reduced to half and intensity of central maxima will be four times.

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