Question
Use identities to evaluate : $(101)^2$
✓
Answer
$(101)^2$
$(101)^2 = (100 + 1)^2$
We know that,
$(a + b)^2 = a^2 + b^2 + 2ab$
$\therefore (100 + 1)^2$
$= 100^2 + 1^2 + 2 \times 100\times 1$
$= 10,000 + 1 + 200$
$= 10,201$
$(101)^2 = (100 + 1)^2$
We know that,
$(a + b)^2 = a^2 + b^2 + 2ab$
$\therefore (100 + 1)^2$
$= 100^2 + 1^2 + 2 \times 100\times 1$
$= 10,000 + 1 + 200$
$= 10,201$
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