Question
Use property to evaluate : $38^3+ (-26)^3+ (-12)^3$
✓
Answer
Property is if $a + b + c = 0$ then $a^3+ b^3+ c^3= 3abc$
$a = 38, b = -26, c = -12$
$38^3+ (-26)^3+ (-12)^3$
$= 3(38)(-26)(-12)$
$= 35568$
$a = 38, b = -26, c = -12$
$38^3+ (-26)^3+ (-12)^3$
$= 3(38)(-26)(-12)$
$= 35568$
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