Question
Use the properties of exponents to verify that each statement is true. $\frac{1}{4}(2^{\text{n}})=2^{\text{n}-2}$
✓
Answer
$\frac{1}{4}(2^{\text{n}})=2^{\text{n}-2}$ $\text{RHS} = 2^{\text{n} - 2} = 2^\text{n} + 2^2 $ $[\because\text{a}^{\text{m}}+\text{a}^{\text{n}}=(\text{a})^{\text{m}-\text{n}}]$ $=\frac{2^{\text{n}}}{4}=\text{LHS}$
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