Question
Use the properties of exponents to verify that each statement is true. $4^{\text{n}-1}=\frac{1}{4}(4)^{\text{n}}$

Answer

$4^{\text{n}-1}=\frac{1}{4}(4)^{\text{n}}$ $\text{LHS} = 4^{\text{n} - 1} = 4^\text{n} + 4^1$ $[\because\text{a}^{\text{m}}+\text{a}^{\text{n}}=(\text{a})^{\text{m}-\text{n}}]$ $=\frac{4^{\text{n}}}{4}=\text{RHS}$

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