MCQ
Using binomial theorem, the value of (0.999)3 correct to 3 decimal places is:
- A0.999
- B0.998
- C0.997
- D0.995
Solution:
(0.999)3 = (1 - 0.001)3
= 3C0 - 3C1 (0.001) + 3C2 (0.001)2 - 3C3 (0.001)3
= 1 - 0.003 + 3 (0.000001) - (0.000000001)
= 0.997
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