MCQ
Using binomial theorem, the value of (0.999)3 correct to 3 decimal places is:
    • A
      0.999
    • B
      0.998
    • C
      0.997
    • D
      0.995

    Answer

    1. 0.997

    Solution:

    (0.999)3 = (1 - 0.001)3

    = 3​C0​ - 3​C​(0.001) + 3​C​(0.001)2 - 3​C3​ (0.001)3

    = 1 - 0.003 + 3 (0.000001) - (0.000000001)

    = 0.997

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