Question
Using contrapositive method prove that if n 2 is an even integer, then n is also an even integers.

Answer

Let p: n2 is an even integer.
q: n is also an even integer.
Let ~p is true i.e., n is not an even integer.
⇒ n2 is not an even integer. [Since square of an odd integer is odd]
⇒ ~p is true.
Therefore, ~q is true which provides that ~p is true.
Hence proved.

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