Question
Using differentials, find the approximate values of the following:
$\frac{1}{(2.002)^2}$
$\frac{1}{(2.002)^2}$
Let:
x = 2 $\text{x}+\triangle \text{x}=2.002$Then,
$\triangle\text{x}=- 0.002$ For x = 2 $\text{y}=\frac{1} {2^2}=\frac{1}{4}$Let:
$\text{dx}=\triangle \text{x}=0.002$Now, $\text{y}=\frac{1} {\text{x}^2}$
$\Rightarrow\frac {\text{dy}}{\text{dx}}=\frac{2}{\text{x} ^3}$ $\Rightarrow\Big(\frac {\text{dy}}{\text{dx}}\Big)_{\text{x}=2} =\frac{1}{4}$ $\therefore\triangle \text{y}=\text{dy}=\frac{\text{dy}} {\text{dx}}\text{dx}=\frac{1}{4}\times- 0.002=-0.005$ $\Rightarrow\triangle \text{y}=-0.0005$ $\therefore\frac{1} {(2.002)^2}=\text{y}+\triangle\text{y} =0.2495$Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| | Area occupied by the machine | Labour force for each machine | Daliy outputin units |
| Machines | 1000 sp.m | 12 mem | 60 |
| Machines | 1200 sp.m | 8 mem | 40 |