Question
Using divisibility tests, determine if $5445$ is divisible by $11.$
✓
Answer
Sum of the digits (at odd places) from the right $= 5 + 4 = 9$
Sum of the digits (at even places) from the right $= 4 + 5 = 9$
Difference of these sums $= 9 – 9 = 0$
$\therefore 5445$ is divisible by $11$ because a no. is divisible by $11$ if difference of sums of digits at odd places and even places ( from right) is either 0 or divisible by $11$
Sum of the digits (at even places) from the right $= 4 + 5 = 9$
Difference of these sums $= 9 – 9 = 0$
$\therefore 5445$ is divisible by $11$ because a no. is divisible by $11$ if difference of sums of digits at odd places and even places ( from right) is either 0 or divisible by $11$
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