Question
Using elementary row operations, find the inverse of the following matrix:

$\begin{pmatrix} 2 & 5 \\ 1 & 3 \\ \end{pmatrix}$.

Answer

Here A = $\begin{pmatrix} 2 & 5 \\ 1 & 3 \\ \end{pmatrix}$
Writing A= IA $\Rightarrow$ $\begin{vmatrix} 2 & 5 \\ 1 & 3 \\ \end{vmatrix}=\begin{vmatrix} 1 & 0 \\ 0 & 1 \\ \end{vmatrix}\text{A}$
Applying R1 $\rightarrow$ R- R2, we get
$\begin{vmatrix} 1 & 2 \\ 1 & 3 \\ \end{vmatrix}=\begin{vmatrix} 1 & -1 \\ 0 & 1 \\ \end{vmatrix}\text{A}$
Applying R2 $\rightarrow$ R- R1, we get $\begin{bmatrix} 1 & 2 \\ 1 & 3 \\ \end{bmatrix}$$\begin{bmatrix} 1 & -1 \\ -1 & 2 \\ \end{bmatrix}\text{A}$
Applying R1 $\rightarrow$ R- 2R2, we get $\begin{bmatrix} 1 & 0 \\ 0 & 1 \\ \end{bmatrix}$$\begin{bmatrix} 3 & -5 \\ -1 & 2 \\ \end{bmatrix}\text{A}$
$\Rightarrow\text{A}^{-1}=\begin{bmatrix} 3 & -5 \\ -1 & 2 \\ \end{bmatrix}$.

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