Question
Using factor theorem, show that g(x) is a factor of p(x), when
p(x) = x4 - x2 - 12, g(x) = x + 2
p(x) = x4 - x2 - 12, g(x) = x + 2
✓
Answer
f(x) = (x4 - x2 - 12)
By the Factor Theorem, (x + 2) will be a factor of f(x) if f(-2) = 0.
Here, f(-2) = (-2)4 - (-2)2 - 12
= 16 - 4 - 12
= 16 - 16 = 0
$\therefore$ (x + 2) is a factor of (x4 - x2 - 12).
By the Factor Theorem, (x + 2) will be a factor of f(x) if f(-2) = 0.
Here, f(-2) = (-2)4 - (-2)2 - 12
= 16 - 4 - 12
= 16 - 16 = 0
$\therefore$ (x + 2) is a factor of (x4 - x2 - 12).
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2. What is the volume of the planter?