Question
Using Gauss’s law in electrostatics, deduce an expression for electric field intensity due to a uniformly charged infinite plane sheet. If another identical sheet is placed parallel to it, show that there is no electric field in the region between the two sheets.

Answer


By Gauss’s law $ \oint \overrightarrow{E}.\overrightarrow{ds}=\frac{q}{\in_0}$
$\therefore{2{\text{EA}}}=\frac{\sigma{\text{A}}}{{\in_0}}$
$\therefore\text{E}=\frac{\sigma}{2\in_0}\text{ }\text{or}\frac{\sigma}{2\in_0}\text{A}$
Electric field between two identical charged sheets

$\because$ Both the sheets have same charge density, their electric fields will be equal and opposite in the region between the two sheets.
Hence the net field is zero.Alternate Answer
$\text{E}_1=\frac{\sigma}{2\in_0}$
$\text{E}_2=-\frac{\sigma}{2\in_0}$
Resultant electric field between the plates $= E_1 + E_2\frac{\sigma}{2\in_0}-\frac{\sigma}{2\in_0}=0$]

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